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2\sin(3\pi )-\cos(2\pi )+6c=0
Multiply both sides of the equation by 6, the least common multiple of 3,6.
2\sin(3\pi )-1+6c=0
Get the value of \cos(2\pi ) from trigonometric values table.
-1+6c=-2\sin(3\pi )
Subtract 2\sin(3\pi ) from both sides. Anything subtracted from zero gives its negation.
6c=-2\sin(3\pi )+1
Add 1 to both sides.
\frac{6c}{6}=\frac{1}{6}
Divide both sides by 6.
c=\frac{1}{6}
Dividing by 6 undoes the multiplication by 6.