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\frac{3+\sqrt[3]{-27}}{6}
The base 2 logarithm of 8 is 3.
\frac{3-3}{6}
Calculate \sqrt[3]{-27} and get -3.
\frac{0}{6}
Subtract 3 from 3 to get 0.
0
Zero divided by any non-zero number gives zero.