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\frac{\left(x-1\right)\left(3-x\right)}{\left(x+1\right)\left(1-x\right)}
Divide \frac{x-1}{x+1} by \frac{1-x}{3-x} by multiplying \frac{x-1}{x+1} by the reciprocal of \frac{1-x}{3-x}.
\frac{-\left(-x+1\right)\left(-x+3\right)}{\left(x+1\right)\left(-x+1\right)}
Extract the negative sign in x-1.
\frac{-\left(-x+3\right)}{x+1}
Cancel out -x+1 in both numerator and denominator.
\frac{-\left(-x\right)-3}{x+1}
To find the opposite of -x+3, find the opposite of each term.
\frac{x-3}{x+1}
The opposite of -x is x.
\frac{\left(x-1\right)\left(3-x\right)}{\left(x+1\right)\left(1-x\right)}
Divide \frac{x-1}{x+1} by \frac{1-x}{3-x} by multiplying \frac{x-1}{x+1} by the reciprocal of \frac{1-x}{3-x}.
\frac{-\left(-x+1\right)\left(-x+3\right)}{\left(x+1\right)\left(-x+1\right)}
Extract the negative sign in x-1.
\frac{-\left(-x+3\right)}{x+1}
Cancel out -x+1 in both numerator and denominator.
\frac{-\left(-x\right)-3}{x+1}
To find the opposite of -x+3, find the opposite of each term.
\frac{x-3}{x+1}
The opposite of -x is x.