Evaluate
\frac{2\left(x+3\right)}{x+2}
Expand
\frac{2\left(x+3\right)}{x+2}
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\frac{\frac{x+3}{x+1}+\frac{3\left(x+3\right)}{x+1}}{\frac{x+3}{x+1}+1}
Divide x+1 by x+1 to get 1.
\frac{\frac{x+3+3\left(x+3\right)}{x+1}}{\frac{x+3}{x+1}+1}
Since \frac{x+3}{x+1} and \frac{3\left(x+3\right)}{x+1} have the same denominator, add them by adding their numerators.
\frac{\frac{x+3+3x+9}{x+1}}{\frac{x+3}{x+1}+1}
Do the multiplications in x+3+3\left(x+3\right).
\frac{\frac{4x+12}{x+1}}{\frac{x+3}{x+1}+1}
Combine like terms in x+3+3x+9.
\frac{\frac{4x+12}{x+1}}{\frac{x+3}{x+1}+\frac{x+1}{x+1}}
To add or subtract expressions, expand them to make their denominators the same. Multiply 1 times \frac{x+1}{x+1}.
\frac{\frac{4x+12}{x+1}}{\frac{x+3+x+1}{x+1}}
Since \frac{x+3}{x+1} and \frac{x+1}{x+1} have the same denominator, add them by adding their numerators.
\frac{\frac{4x+12}{x+1}}{\frac{2x+4}{x+1}}
Combine like terms in x+3+x+1.
\frac{\left(4x+12\right)\left(x+1\right)}{\left(x+1\right)\left(2x+4\right)}
Divide \frac{4x+12}{x+1} by \frac{2x+4}{x+1} by multiplying \frac{4x+12}{x+1} by the reciprocal of \frac{2x+4}{x+1}.
\frac{4x+12}{2x+4}
Cancel out x+1 in both numerator and denominator.
\frac{4\left(x+3\right)}{2\left(x+2\right)}
Factor the expressions that are not already factored.
\frac{2\left(x+3\right)}{x+2}
Cancel out 2 in both numerator and denominator.
\frac{2x+6}{x+2}
Expand the expression.
\frac{\frac{x+3}{x+1}+\frac{3\left(x+3\right)}{x+1}}{\frac{x+3}{x+1}+1}
Divide x+1 by x+1 to get 1.
\frac{\frac{x+3+3\left(x+3\right)}{x+1}}{\frac{x+3}{x+1}+1}
Since \frac{x+3}{x+1} and \frac{3\left(x+3\right)}{x+1} have the same denominator, add them by adding their numerators.
\frac{\frac{x+3+3x+9}{x+1}}{\frac{x+3}{x+1}+1}
Do the multiplications in x+3+3\left(x+3\right).
\frac{\frac{4x+12}{x+1}}{\frac{x+3}{x+1}+1}
Combine like terms in x+3+3x+9.
\frac{\frac{4x+12}{x+1}}{\frac{x+3}{x+1}+\frac{x+1}{x+1}}
To add or subtract expressions, expand them to make their denominators the same. Multiply 1 times \frac{x+1}{x+1}.
\frac{\frac{4x+12}{x+1}}{\frac{x+3+x+1}{x+1}}
Since \frac{x+3}{x+1} and \frac{x+1}{x+1} have the same denominator, add them by adding their numerators.
\frac{\frac{4x+12}{x+1}}{\frac{2x+4}{x+1}}
Combine like terms in x+3+x+1.
\frac{\left(4x+12\right)\left(x+1\right)}{\left(x+1\right)\left(2x+4\right)}
Divide \frac{4x+12}{x+1} by \frac{2x+4}{x+1} by multiplying \frac{4x+12}{x+1} by the reciprocal of \frac{2x+4}{x+1}.
\frac{4x+12}{2x+4}
Cancel out x+1 in both numerator and denominator.
\frac{4\left(x+3\right)}{2\left(x+2\right)}
Factor the expressions that are not already factored.
\frac{2\left(x+3\right)}{x+2}
Cancel out 2 in both numerator and denominator.
\frac{2x+6}{x+2}
Expand the expression.
Examples
Quadratic equation
{ x } ^ { 2 } - 4 x - 5 = 0
Trigonometry
4 \sin \theta \cos \theta = 2 \sin \theta
Linear equation
y = 3x + 4
Arithmetic
699 * 533
Matrix
\left[ \begin{array} { l l } { 2 } & { 3 } \\ { 5 } & { 4 } \end{array} \right] \left[ \begin{array} { l l l } { 2 } & { 0 } & { 3 } \\ { -1 } & { 1 } & { 5 } \end{array} \right]
Simultaneous equation
\left. \begin{cases} { 8x+2y = 46 } \\ { 7x+3y = 47 } \end{cases} \right.
Differentiation
\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
Integration
\int _ { 0 } ^ { 1 } x e ^ { - x ^ { 2 } } d x
Limits
\lim _{x \rightarrow-3} \frac{x^{2}-9}{x^{2}+2 x-3}