Solve 8a^4b^3/3c/frac{a^7b^2{9c}}

$$\frac { \frac { 8 a ^ { 4 } b ^ { 3 } } { 3 c } } { \frac { a ^ { 7 } b ^ { 2 } } { 9 c } }$$

Evaluate

$$\frac{24b}{a^{3}}$$

Solution Steps

Divide \frac{8a^{4}b^{3}}{3c} by \frac{a^{7}b^{2}}{9c} by multiplying \frac{8a^{4}b^{3}}{3c} by the reciprocal of \frac{a^{7}b^{2}}{9c}.

$$\frac{8a^{4}b^{3}\times 9c}{3ca^{7}b^{2}}$$

Cancel out 3cb^{2}a^{4} in both numerator and denominator.

$$\frac{3\times 8b}{a^{3}}$$

Multiply 3 and 8 to get 24.

$$\frac{24b}{a^{3}}$$

Differentiate w.r.t. b

$$\frac{24}{a^{3}}$$