Solve 8/7-(1/3)^2/frac{1{3}}=

$$\frac { \frac { 8 } { 7 } - ( \frac { 1 } { 3 } ) ^ { 2 } } { \frac { 1 } { 3 } } =$$

Evaluate

$$\frac{65}{21}\approx 3.095238095$$

Solution Steps

Calculate \frac{1}{3} to the power of 2 and get \frac{1}{9}.

$$\frac{\frac{8}{7}-\frac{1}{9}}{\frac{1}{3}}$$

Least common multiple of 7 and 9 is 63. Convert \frac{8}{7} and \frac{1}{9} to fractions with denominator 63.

$$\frac{\frac{72}{63}-\frac{7}{63}}{\frac{1}{3}}$$

Since \frac{72}{63} and \frac{7}{63} have the same denominator, subtract them by subtracting their numerators.

$$\frac{\frac{72-7}{63}}{\frac{1}{3}}$$

Subtract 7 from 72 to get 65.

$$\frac{\frac{65}{63}}{\frac{1}{3}}$$

Divide \frac{65}{63} by \frac{1}{3} by multiplying \frac{65}{63} by the reciprocal of \frac{1}{3}.

$$\frac{65}{63}\times 3$$

Express \frac{65}{63}\times 3 as a single fraction.

$$\frac{65\times 3}{63}$$

Multiply 65 and 3 to get 195.

$$\frac{195}{63}$$

Reduce the fraction \frac{195}{63} to lowest terms by extracting and canceling out 3.

$$\frac{65}{21}$$

Factor

$$\frac{5 \cdot 13}{3 \cdot 7} = 3\frac{2}{21} = 3.0952380952380953$$