Solve 7/10-1/frac{8{3}+x}

$$\frac { \frac { 7 } { 10 } - 1 } { \frac { 8 } { 3 } + x }$$

Evaluate

$$-\frac{9}{10\left(3x+8\right)}$$

Solution Steps

Convert 1 to fraction \frac{10}{10}.

$$\frac{\frac{7}{10}-\frac{10}{10}}{\frac{8}{3}+x}$$

Since \frac{7}{10} and \frac{10}{10} have the same denominator, subtract them by subtracting their numerators.

$$\frac{\frac{7-10}{10}}{\frac{8}{3}+x}$$

Subtract 10 from 7 to get -3.

$$\frac{-\frac{3}{10}}{\frac{8}{3}+x}$$

Express \frac{-\frac{3}{10}}{\frac{8}{3}+x} as a single fraction.

$$\frac{-3}{10\left(\frac{8}{3}+x\right)}$$

Use the distributive property to multiply 10 by \frac{8}{3}+x.

$$\frac{-3}{10\times \frac{8}{3}+10x}$$

Express 10\times \frac{8}{3} as a single fraction.

$$\frac{-3}{\frac{10\times 8}{3}+10x}$$

Multiply 10 and 8 to get 80.

$$\frac{-3}{\frac{80}{3}+10x}$$

Expand

$$-\frac{3}{10\left(x+\frac{8}{3}\right)}$$

Solution Steps

Convert 1 to fraction \frac{10}{10}.

$$\frac{\frac{7}{10}-\frac{10}{10}}{\frac{8}{3}+x}$$

Since \frac{7}{10} and \frac{10}{10} have the same denominator, subtract them by subtracting their numerators.

$$\frac{\frac{7-10}{10}}{\frac{8}{3}+x}$$

Subtract 10 from 7 to get -3.

$$\frac{-\frac{3}{10}}{\frac{8}{3}+x}$$

Express \frac{-\frac{3}{10}}{\frac{8}{3}+x} as a single fraction.

$$\frac{-3}{10\left(\frac{8}{3}+x\right)}$$

Use the distributive property to multiply 10 by \frac{8}{3}+x.

$$\frac{-3}{10\times \frac{8}{3}+10x}$$

Express 10\times \frac{8}{3} as a single fraction.

$$\frac{-3}{\frac{10\times 8}{3}+10x}$$

Multiply 10 and 8 to get 80.

$$\frac{-3}{\frac{80}{3}+10x}$$