Solve 60/19*60/7/frac{60{19}+60/7}=

$$\frac { \frac { 60 } { 19 } \times \frac { 60 } { 7 } } { \frac { 60 } { 19 } + \frac { 60 } { 7 } } =$$

Evaluate

$$\frac{30}{13}\approx 2.307692308$$

Solution Steps

Multiply \frac{60}{19} times \frac{60}{7} by multiplying numerator times numerator and denominator times denominator.

$$\frac{\frac{60\times 60}{19\times 7}}{\frac{60}{19}+\frac{60}{7}}$$

Do the multiplications in the fraction \frac{60\times 60}{19\times 7}.

$$\frac{\frac{3600}{133}}{\frac{60}{19}+\frac{60}{7}}$$

Least common multiple of 19 and 7 is 133. Convert \frac{60}{19} and \frac{60}{7} to fractions with denominator 133.

$$\frac{\frac{3600}{133}}{\frac{420}{133}+\frac{1140}{133}}$$

Since \frac{420}{133} and \frac{1140}{133} have the same denominator, add them by adding their numerators.

$$\frac{\frac{3600}{133}}{\frac{420+1140}{133}}$$

Add 420 and 1140 to get 1560.

$$\frac{\frac{3600}{133}}{\frac{1560}{133}}$$

Divide \frac{3600}{133} by \frac{1560}{133} by multiplying \frac{3600}{133} by the reciprocal of \frac{1560}{133}.

$$\frac{3600}{133}\times \frac{133}{1560}$$

Multiply \frac{3600}{133} times \frac{133}{1560} by multiplying numerator times numerator and denominator times denominator.

$$\frac{3600\times 133}{133\times 1560}$$

Cancel out 133 in both numerator and denominator.

$$\frac{3600}{1560}$$

Reduce the fraction \frac{3600}{1560} to lowest terms by extracting and canceling out 120.

$$\frac{30}{13}$$

Factor

$$\frac{2 \cdot 3 \cdot 5}{13} = 2\frac{4}{13} = 2.3076923076923075$$