Solve 6/7*3/5/frac{6{7}+3/5}

$$\frac { \frac { 6 } { 7 } \times \frac { 3 } { 5 } } { \frac { 6 } { 7 } + \frac { 3 } { 5 } }$$

Evaluate

$$\frac{6}{17}\approx 0.352941176$$

Solution Steps

Multiply \frac{6}{7} times \frac{3}{5} by multiplying numerator times numerator and denominator times denominator.

$$\frac{\frac{6\times 3}{7\times 5}}{\frac{6}{7}+\frac{3}{5}}$$

Do the multiplications in the fraction \frac{6\times 3}{7\times 5}.

$$\frac{\frac{18}{35}}{\frac{6}{7}+\frac{3}{5}}$$

Least common multiple of 7 and 5 is 35. Convert \frac{6}{7} and \frac{3}{5} to fractions with denominator 35.

$$\frac{\frac{18}{35}}{\frac{30}{35}+\frac{21}{35}}$$

Since \frac{30}{35} and \frac{21}{35} have the same denominator, add them by adding their numerators.

$$\frac{\frac{18}{35}}{\frac{30+21}{35}}$$

Add 30 and 21 to get 51.

$$\frac{\frac{18}{35}}{\frac{51}{35}}$$

Divide \frac{18}{35} by \frac{51}{35} by multiplying \frac{18}{35} by the reciprocal of \frac{51}{35}.

$$\frac{18}{35}\times \frac{35}{51}$$

Multiply \frac{18}{35} times \frac{35}{51} by multiplying numerator times numerator and denominator times denominator.

$$\frac{18\times 35}{35\times 51}$$

Cancel out 35 in both numerator and denominator.

$$\frac{18}{51}$$

Reduce the fraction \frac{18}{51} to lowest terms by extracting and canceling out 3.

$$\frac{6}{17}$$

Factor

$$\frac{2 \cdot 3}{17} = 0.35294117647058826$$