Solve 41/(4-2)!2!*43!/(3-1)!*1/220

$$\frac { \frac { 41 } { ( 4 - 2 ) ! 2 ! } \cdot 4 \frac { 3 ! } { ( 3 - 1 ) ! \cdot 1 } } { 220 }$$

Evaluate

$$\frac{123}{220}\approx 0.559090909$$

Solution Steps

Subtract 2 from 4 to get 2.

$$\frac{\frac{41}{2!\times 2!}\times 4\times \frac{3!}{\left(3-1\right)!\times 1}}{220}$$

The factorial of 2 is 2.

$$\frac{\frac{41}{2\times 2!}\times 4\times \frac{3!}{\left(3-1\right)!\times 1}}{220}$$

The factorial of 2 is 2.

$$\frac{\frac{41}{2\times 2}\times 4\times \frac{3!}{\left(3-1\right)!\times 1}}{220}$$

Multiply 2 and 2 to get 4.

$$\frac{\frac{41}{4}\times 4\times \frac{3!}{\left(3-1\right)!\times 1}}{220}$$

Cancel out 4 and 4.

$$\frac{41\times \frac{3!}{\left(3-1\right)!\times 1}}{220}$$

The factorial of 3 is 6.

$$\frac{41\times \frac{6}{\left(3-1\right)!\times 1}}{220}$$

Subtract 1 from 3 to get 2.

$$\frac{41\times \frac{6}{2!\times 1}}{220}$$

The factorial of 2 is 2.

$$\frac{41\times \frac{6}{2\times 1}}{220}$$

Multiply 2 and 1 to get 2.

$$\frac{41\times \frac{6}{2}}{220}$$

Divide 6 by 2 to get 3.

$$\frac{41\times 3}{220}$$

Multiply 41 and 3 to get 123.

$$\frac{123}{220}$$

Factor

$$\frac{3 \cdot 41}{2 ^ {2} \cdot 5 \cdot 11} = 0.5590909090909091$$