Solve 4x^3/15*4x^2/15/frac{28{45}}

$$\frac { \frac { 4 x ^ { 3 } } { 15 } \cdot \frac { 4 x ^ { 2 } } { 15 } } { \frac { 28 } { 45 } }$$

Evaluate

$$\frac{4x^{5}}{35}$$

Solution Steps

Multiply \frac{4x^{3}}{15} times \frac{4x^{2}}{15} by multiplying numerator times numerator and denominator times denominator.

$$\frac{\frac{4x^{3}\times 4x^{2}}{15\times 15}}{\frac{28}{45}}$$

Divide \frac{4x^{3}\times 4x^{2}}{15\times 15} by \frac{28}{45} by multiplying \frac{4x^{3}\times 4x^{2}}{15\times 15} by the reciprocal of \frac{28}{45}.

$$\frac{4x^{3}\times 4x^{2}\times 45}{15\times 15\times 28}$$

Cancel out 3\times 4\times 15 in both numerator and denominator.

$$\frac{4x^{2}x^{3}}{5\times 7}$$

To multiply powers of the same base, add their exponents. Add 2 and 3 to get 5.

$$\frac{4x^{5}}{5\times 7}$$

Multiply 5 and 7 to get 35.

$$\frac{4x^{5}}{35}$$

Differentiate w.r.t. x

$$\frac{4x^{4}}{7}$$