Solve 4/5*(7/3-1/1)/frac{2{9}-3}

$$\frac { \frac { 4 } { 5 } \cdot ( \frac { 7 } { 3 } - \frac { 1 } { 1 } ) } { \frac { 2 } { 9 } - 3 }$$

Evaluate

$$-\frac{48}{125}=-0.384$$

Solution Steps

Divide 1 by 1 to get 1.

$$\frac{\frac{4}{5}\left(\frac{7}{3}-1\right)}{\frac{2}{9}-3}$$

Convert 1 to fraction \frac{3}{3}.

$$\frac{\frac{4}{5}\left(\frac{7}{3}-\frac{3}{3}\right)}{\frac{2}{9}-3}$$

Since \frac{7}{3} and \frac{3}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{\frac{4}{5}\times \frac{7-3}{3}}{\frac{2}{9}-3}$$

Subtract 3 from 7 to get 4.

$$\frac{\frac{4}{5}\times \frac{4}{3}}{\frac{2}{9}-3}$$

Multiply \frac{4}{5} times \frac{4}{3} by multiplying numerator times numerator and denominator times denominator.

$$\frac{\frac{4\times 4}{5\times 3}}{\frac{2}{9}-3}$$

Do the multiplications in the fraction \frac{4\times 4}{5\times 3}.

$$\frac{\frac{16}{15}}{\frac{2}{9}-3}$$

Convert 3 to fraction \frac{27}{9}.

$$\frac{\frac{16}{15}}{\frac{2}{9}-\frac{27}{9}}$$

Since \frac{2}{9} and \frac{27}{9} have the same denominator, subtract them by subtracting their numerators.

$$\frac{\frac{16}{15}}{\frac{2-27}{9}}$$

Subtract 27 from 2 to get -25.

$$\frac{\frac{16}{15}}{-\frac{25}{9}}$$

Divide \frac{16}{15} by -\frac{25}{9} by multiplying \frac{16}{15} by the reciprocal of -\frac{25}{9}.

$$\frac{16}{15}\left(-\frac{9}{25}\right)$$

Multiply \frac{16}{15} times -\frac{9}{25} by multiplying numerator times numerator and denominator times denominator.

$$\frac{16\left(-9\right)}{15\times 25}$$

Do the multiplications in the fraction \frac{16\left(-9\right)}{15\times 25}.

$$\frac{-144}{375}$$

Reduce the fraction \frac{-144}{375} to lowest terms by extracting and canceling out 3.

$$-\frac{48}{125}$$

Factor

$$-\frac{48}{125} = -0.384$$