Solve 4/3*6/12/21

$$\frac { \frac { 4 } { 3 } \cdot \frac { 6 } { 12 } } { 21 }$$

Evaluate

$$\frac{2}{63}\approx 0.031746032$$

Solution Steps

Reduce the fraction \frac{6}{12} to lowest terms by extracting and canceling out 6.

$$\frac{\frac{4}{3}\times \frac{1}{2}}{21}$$

Multiply \frac{4}{3} times \frac{1}{2} by multiplying numerator times numerator and denominator times denominator.

$$\frac{\frac{4\times 1}{3\times 2}}{21}$$

Do the multiplications in the fraction \frac{4\times 1}{3\times 2}.

$$\frac{\frac{4}{6}}{21}$$

Reduce the fraction \frac{4}{6} to lowest terms by extracting and canceling out 2.

$$\frac{\frac{2}{3}}{21}$$

Express \frac{\frac{2}{3}}{21} as a single fraction.

$$\frac{2}{3\times 21}$$

Multiply 3 and 21 to get 63.

$$\frac{2}{63}$$

Factor

$$\frac{2}{3 ^ {2} \cdot 7} = 0.031746031746031744$$