Solve for x
x=8
x=-8
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\frac{3}{4}x^{2}=24\times 2
Multiply both sides by 2.
\frac{3}{4}x^{2}=48
Multiply 24 and 2 to get 48.
\frac{3}{4}x^{2}-48=0
Subtract 48 from both sides.
x^{2}-64=0
Divide both sides by \frac{3}{4}.
\left(x-8\right)\left(x+8\right)=0
Consider x^{2}-64. Rewrite x^{2}-64 as x^{2}-8^{2}. The difference of squares can be factored using the rule: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).
x=8 x=-8
To find equation solutions, solve x-8=0 and x+8=0.
\frac{3}{4}x^{2}=24\times 2
Multiply both sides by 2.
\frac{3}{4}x^{2}=48
Multiply 24 and 2 to get 48.
x^{2}=48\times \frac{4}{3}
Multiply both sides by \frac{4}{3}, the reciprocal of \frac{3}{4}.
x^{2}=64
Multiply 48 and \frac{4}{3} to get 64.
x=8 x=-8
Take the square root of both sides of the equation.
\frac{3}{4}x^{2}=24\times 2
Multiply both sides by 2.
\frac{3}{4}x^{2}=48
Multiply 24 and 2 to get 48.
\frac{3}{4}x^{2}-48=0
Subtract 48 from both sides.
x=\frac{0±\sqrt{0^{2}-4\times \frac{3}{4}\left(-48\right)}}{2\times \frac{3}{4}}
This equation is in standard form: ax^{2}+bx+c=0. Substitute \frac{3}{4} for a, 0 for b, and -48 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{0±\sqrt{-4\times \frac{3}{4}\left(-48\right)}}{2\times \frac{3}{4}}
Square 0.
x=\frac{0±\sqrt{-3\left(-48\right)}}{2\times \frac{3}{4}}
Multiply -4 times \frac{3}{4}.
x=\frac{0±\sqrt{144}}{2\times \frac{3}{4}}
Multiply -3 times -48.
x=\frac{0±12}{2\times \frac{3}{4}}
Take the square root of 144.
x=\frac{0±12}{\frac{3}{2}}
Multiply 2 times \frac{3}{4}.
x=8
Now solve the equation x=\frac{0±12}{\frac{3}{2}} when ± is plus. Divide 12 by \frac{3}{2} by multiplying 12 by the reciprocal of \frac{3}{2}.
x=-8
Now solve the equation x=\frac{0±12}{\frac{3}{2}} when ± is minus. Divide -12 by \frac{3}{2} by multiplying -12 by the reciprocal of \frac{3}{2}.
x=8 x=-8
The equation is now solved.
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