Solve 3/4-1/2/frac{1{3}*1/2}=

$$\frac { \frac { 3 } { 4 } - \frac { 1 } { 2 } } { \frac { 1 } { 3 } \cdot \frac { 1 } { 2 } } =$$

Evaluate

$$\frac{3}{2}=1.5$$

Solution Steps

Least common multiple of 4 and 2 is 4. Convert \frac{3}{4} and \frac{1}{2} to fractions with denominator 4.

$$\frac{\frac{3}{4}-\frac{2}{4}}{\frac{1}{3}\times \frac{1}{2}}$$

Since \frac{3}{4} and \frac{2}{4} have the same denominator, subtract them by subtracting their numerators.

$$\frac{\frac{3-2}{4}}{\frac{1}{3}\times \frac{1}{2}}$$

Subtract 2 from 3 to get 1.

$$\frac{\frac{1}{4}}{\frac{1}{3}\times \frac{1}{2}}$$

Multiply \frac{1}{3} times \frac{1}{2} by multiplying numerator times numerator and denominator times denominator.

$$\frac{\frac{1}{4}}{\frac{1\times 1}{3\times 2}}$$

Do the multiplications in the fraction \frac{1\times 1}{3\times 2}.

$$\frac{\frac{1}{4}}{\frac{1}{6}}$$

Divide \frac{1}{4} by \frac{1}{6} by multiplying \frac{1}{4} by the reciprocal of \frac{1}{6}.

$$\frac{1}{4}\times 6$$

Multiply \frac{1}{4} and 6 to get \frac{6}{4}.

$$\frac{6}{4}$$

Reduce the fraction \frac{6}{4} to lowest terms by extracting and canceling out 2.

$$\frac{3}{2}$$

Factor

$$\frac{3}{2} = 1\frac{1}{2} = 1.5$$