Solve 23/256+3/32/2

$$\frac { \frac { 23 } { 256 } + \frac { 3 } { 32 } } { 2 }$$

Evaluate

$$\frac{47}{512}=0.091796875$$

Solution Steps

Least common multiple of 256 and 32 is 256. Convert \frac{23}{256} and \frac{3}{32} to fractions with denominator 256.

$$\frac{\frac{23}{256}+\frac{24}{256}}{2}$$

Since \frac{23}{256} and \frac{24}{256} have the same denominator, add them by adding their numerators.

$$\frac{\frac{23+24}{256}}{2}$$

Add 23 and 24 to get 47.

$$\frac{\frac{47}{256}}{2}$$

Express \frac{\frac{47}{256}}{2} as a single fraction.

$$\frac{47}{256\times 2}$$

Multiply 256 and 2 to get 512.

$$\frac{47}{512}$$

Factor

$$\frac{47}{2 ^ {9}} = 0.091796875$$