Solve 2/4+1/8/frac{3{2}}=10/24=frac{5}{12}

$$\frac { \frac { 2 } { 4 } + \frac { 1 } { 8 } } { \frac { 3 } { 2 } } = \frac { 10 } { 24 } = \frac { 5 } { 12 }$$

Verify

Solution Steps

Reduce the fraction \frac{2}{4} to lowest terms by extracting and canceling out 2.

$$\frac{\frac{1}{2}+\frac{1}{8}}{\frac{3}{2}}=\frac{10}{24}\text{ and }\frac{10}{24}=\frac{5}{12}$$

Least common multiple of 2 and 8 is 8. Convert \frac{1}{2} and \frac{1}{8} to fractions with denominator 8.

$$\frac{\frac{4}{8}+\frac{1}{8}}{\frac{3}{2}}=\frac{10}{24}\text{ and }\frac{10}{24}=\frac{5}{12}$$

Since \frac{4}{8} and \frac{1}{8} have the same denominator, add them by adding their numerators.

$$\frac{\frac{4+1}{8}}{\frac{3}{2}}=\frac{10}{24}\text{ and }\frac{10}{24}=\frac{5}{12}$$

Add 4 and 1 to get 5.

$$\frac{\frac{5}{8}}{\frac{3}{2}}=\frac{10}{24}\text{ and }\frac{10}{24}=\frac{5}{12}$$

Divide \frac{5}{8} by \frac{3}{2} by multiplying \frac{5}{8} by the reciprocal of \frac{3}{2}.

$$\frac{5}{8}\times \frac{2}{3}=\frac{10}{24}\text{ and }\frac{10}{24}=\frac{5}{12}$$

Multiply \frac{5}{8} times \frac{2}{3} by multiplying numerator times numerator and denominator times denominator.

$$\frac{5\times 2}{8\times 3}=\frac{10}{24}\text{ and }\frac{10}{24}=\frac{5}{12}$$

Do the multiplications in the fraction \frac{5\times 2}{8\times 3}.

$$\frac{10}{24}=\frac{10}{24}\text{ and }\frac{10}{24}=\frac{5}{12}$$

Reduce the fraction \frac{10}{24} to lowest terms by extracting and canceling out 2.

$$\frac{5}{12}=\frac{10}{24}\text{ and }\frac{10}{24}=\frac{5}{12}$$

Reduce the fraction \frac{10}{24} to lowest terms by extracting and canceling out 2.

$$\frac{5}{12}=\frac{5}{12}\text{ and }\frac{10}{24}=\frac{5}{12}$$

Compare \frac{5}{12} and \frac{5}{12}.

$$\text{true}\text{ and }\frac{10}{24}=\frac{5}{12}$$

Reduce the fraction \frac{10}{24} to lowest terms by extracting and canceling out 2.

$$\text{true}\text{ and }\frac{5}{12}=\frac{5}{12}$$

Compare \frac{5}{12} and \frac{5}{12}.

$$\text{true}\text{ and }\text{true}$$

The conjunction of \text{true} and \text{true} is \text{true}.

$$\text{true}$$