Solve 16/63+5/12/1-frac{16{63}*5/12}

$$\frac { \frac { 16 } { 63 } + \frac { 5 } { 12 } } { 1 - \frac { 16 } { 63 } \times \frac { 5 } { 12 } }$$

Evaluate

$$\frac{3}{4}=0.75$$

Solution Steps

Least common multiple of 63 and 12 is 252. Convert \frac{16}{63} and \frac{5}{12} to fractions with denominator 252.

$$\frac{\frac{64}{252}+\frac{105}{252}}{1-\frac{16}{63}\times \frac{5}{12}}$$

Since \frac{64}{252} and \frac{105}{252} have the same denominator, add them by adding their numerators.

$$\frac{\frac{64+105}{252}}{1-\frac{16}{63}\times \frac{5}{12}}$$

Add 64 and 105 to get 169.

$$\frac{\frac{169}{252}}{1-\frac{16}{63}\times \frac{5}{12}}$$

Multiply \frac{16}{63} times \frac{5}{12} by multiplying numerator times numerator and denominator times denominator.

$$\frac{\frac{169}{252}}{1-\frac{16\times 5}{63\times 12}}$$

Do the multiplications in the fraction \frac{16\times 5}{63\times 12}.

$$\frac{\frac{169}{252}}{1-\frac{80}{756}}$$

Reduce the fraction \frac{80}{756} to lowest terms by extracting and canceling out 4.

$$\frac{\frac{169}{252}}{1-\frac{20}{189}}$$

Convert 1 to fraction \frac{189}{189}.

$$\frac{\frac{169}{252}}{\frac{189}{189}-\frac{20}{189}}$$

Since \frac{189}{189} and \frac{20}{189} have the same denominator, subtract them by subtracting their numerators.

$$\frac{\frac{169}{252}}{\frac{189-20}{189}}$$

Subtract 20 from 189 to get 169.

$$\frac{\frac{169}{252}}{\frac{169}{189}}$$

Divide \frac{169}{252} by \frac{169}{189} by multiplying \frac{169}{252} by the reciprocal of \frac{169}{189}.

$$\frac{169}{252}\times \frac{189}{169}$$

Multiply \frac{169}{252} times \frac{189}{169} by multiplying numerator times numerator and denominator times denominator.

$$\frac{169\times 189}{252\times 169}$$

Cancel out 169 in both numerator and denominator.

$$\frac{189}{252}$$

Reduce the fraction \frac{189}{252} to lowest terms by extracting and canceling out 63.

$$\frac{3}{4}$$

Factor

$$\frac{3}{2 ^ {2}} = 0.75$$