Solve 16/4-3x-9/5

$$\frac { \frac { 16 } { 4 - 3 x } - 9 } { 5 }$$

Evaluate

$$\frac{27x-20}{5\left(4-3x\right)}$$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Multiply 9 times \frac{4-3x}{4-3x}.

$$\frac{\frac{16}{4-3x}-\frac{9\left(4-3x\right)}{4-3x}}{5}$$

Since \frac{16}{4-3x} and \frac{9\left(4-3x\right)}{4-3x} have the same denominator, subtract them by subtracting their numerators.

$$\frac{\frac{16-9\left(4-3x\right)}{4-3x}}{5}$$

Do the multiplications in 16-9\left(4-3x\right).

$$\frac{\frac{16-36+27x}{4-3x}}{5}$$

Combine like terms in 16-36+27x.

$$\frac{\frac{-20+27x}{4-3x}}{5}$$

Express \frac{\frac{-20+27x}{4-3x}}{5} as a single fraction.

$$\frac{-20+27x}{\left(4-3x\right)\times 5}$$

Use the distributive property to multiply 4-3x by 5.

$$\frac{-20+27x}{20-15x}$$

Expand

$$\frac{27x-20}{5\left(4-3x\right)}$$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Multiply 9 times \frac{4-3x}{4-3x}.

$$\frac{\frac{16}{4-3x}-\frac{9\left(4-3x\right)}{4-3x}}{5}$$

Since \frac{16}{4-3x} and \frac{9\left(4-3x\right)}{4-3x} have the same denominator, subtract them by subtracting their numerators.

$$\frac{\frac{16-9\left(4-3x\right)}{4-3x}}{5}$$

Do the multiplications in 16-9\left(4-3x\right).

$$\frac{\frac{16-36+27x}{4-3x}}{5}$$

Combine like terms in 16-36+27x.

$$\frac{\frac{-20+27x}{4-3x}}{5}$$

Express \frac{\frac{-20+27x}{4-3x}}{5} as a single fraction.

$$\frac{-20+27x}{\left(4-3x\right)\times 5}$$

Use the distributive property to multiply 4-3x by 5.

$$\frac{-20+27x}{20-15x}$$