Solve 12/12+1/3/frac{14*6{3+4}}

$$\frac { \frac { 12 } { 12 } + \frac { 1 } { 3 } } { \frac { 14 \times 6 } { 3 + 4 } }$$

Evaluate

$$\frac{1}{9}\approx 0.111111111$$

Solution Steps

Divide 12 by 12 to get 1.

$$\frac{1+\frac{1}{3}}{\frac{14\times 6}{3+4}}$$

Convert 1 to fraction \frac{3}{3}.

$$\frac{\frac{3}{3}+\frac{1}{3}}{\frac{14\times 6}{3+4}}$$

Since \frac{3}{3} and \frac{1}{3} have the same denominator, add them by adding their numerators.

$$\frac{\frac{3+1}{3}}{\frac{14\times 6}{3+4}}$$

Add 3 and 1 to get 4.

$$\frac{\frac{4}{3}}{\frac{14\times 6}{3+4}}$$

Multiply 14 and 6 to get 84.

$$\frac{\frac{4}{3}}{\frac{84}{3+4}}$$

Add 3 and 4 to get 7.

$$\frac{\frac{4}{3}}{\frac{84}{7}}$$

Divide 84 by 7 to get 12.

$$\frac{\frac{4}{3}}{12}$$

Express \frac{\frac{4}{3}}{12} as a single fraction.

$$\frac{4}{3\times 12}$$

Multiply 3 and 12 to get 36.

$$\frac{4}{36}$$

Reduce the fraction \frac{4}{36} to lowest terms by extracting and canceling out 4.

$$\frac{1}{9}$$

Factor

$$\frac{1}{3 ^ {2}} = 0.1111111111111111$$