Solve 1/3+2/frac{5{4}+2}

$$\frac { \frac { 1 } { 3 } + 2 } { \frac { 5 } { 4 } + 2 }$$

Evaluate

$$\frac{28}{39}\approx 0.717948718$$

Solution Steps

Convert 2 to fraction \frac{6}{3}.

$$\frac{\frac{1}{3}+\frac{6}{3}}{\frac{5}{4}+2}$$

Since \frac{1}{3} and \frac{6}{3} have the same denominator, add them by adding their numerators.

$$\frac{\frac{1+6}{3}}{\frac{5}{4}+2}$$

Add 1 and 6 to get 7.

$$\frac{\frac{7}{3}}{\frac{5}{4}+2}$$

Convert 2 to fraction \frac{8}{4}.

$$\frac{\frac{7}{3}}{\frac{5}{4}+\frac{8}{4}}$$

Since \frac{5}{4} and \frac{8}{4} have the same denominator, add them by adding their numerators.

$$\frac{\frac{7}{3}}{\frac{5+8}{4}}$$

Add 5 and 8 to get 13.

$$\frac{\frac{7}{3}}{\frac{13}{4}}$$

Divide \frac{7}{3} by \frac{13}{4} by multiplying \frac{7}{3} by the reciprocal of \frac{13}{4}.

$$\frac{7}{3}\times \frac{4}{13}$$

Multiply \frac{7}{3} times \frac{4}{13} by multiplying numerator times numerator and denominator times denominator.

$$\frac{7\times 4}{3\times 13}$$

Do the multiplications in the fraction \frac{7\times 4}{3\times 13}.

$$\frac{28}{39}$$

Factor

$$\frac{2 ^ {2} \cdot 7}{3 \cdot 13} = 0.717948717948718$$