Solve 1/3+1/frac{1{3}-(-1)}

$$\frac { \frac { 1 } { 3 } + 1 } { \frac { 1 } { 3 } - ( - 1 ) }$$

Evaluate

$$1$$

Solution Steps

Convert 1 to fraction \frac{3}{3}.

$$\frac{\frac{1}{3}+\frac{3}{3}}{\frac{1}{3}-\left(-1\right)}$$

Since \frac{1}{3} and \frac{3}{3} have the same denominator, add them by adding their numerators.

$$\frac{\frac{1+3}{3}}{\frac{1}{3}-\left(-1\right)}$$

Add 1 and 3 to get 4.

$$\frac{\frac{4}{3}}{\frac{1}{3}-\left(-1\right)}$$

The opposite of -1 is 1.

$$\frac{\frac{4}{3}}{\frac{1}{3}+1}$$

Convert 1 to fraction \frac{3}{3}.

$$\frac{\frac{4}{3}}{\frac{1}{3}+\frac{3}{3}}$$

Since \frac{1}{3} and \frac{3}{3} have the same denominator, add them by adding their numerators.

$$\frac{\frac{4}{3}}{\frac{1+3}{3}}$$

Add 1 and 3 to get 4.

$$\frac{\frac{4}{3}}{\frac{4}{3}}$$

Divide \frac{4}{3} by \frac{4}{3} to get 1.

$$1$$

Factor

$$1$$