Solve 1/3+1/8-1/3/frac{1{8}+frac{1}{2}}=

$$\frac { \frac { 1 } { 3 } + \frac { 1 } { 8 } - \frac { 1 } { 3 } } { \frac { 1 } { 8 } + \frac { 1 } { 2 } } =$$

Evaluate

$$\frac{1}{5}=0.2$$

Solution Steps

Least common multiple of 3 and 8 is 24. Convert \frac{1}{3} and \frac{1}{8} to fractions with denominator 24.

$$\frac{\frac{8}{24}+\frac{3}{24}-\frac{1}{3}}{\frac{1}{8}+\frac{1}{2}}$$

Since \frac{8}{24} and \frac{3}{24} have the same denominator, add them by adding their numerators.

$$\frac{\frac{8+3}{24}-\frac{1}{3}}{\frac{1}{8}+\frac{1}{2}}$$

Add 8 and 3 to get 11.

$$\frac{\frac{11}{24}-\frac{1}{3}}{\frac{1}{8}+\frac{1}{2}}$$

Least common multiple of 24 and 3 is 24. Convert \frac{11}{24} and \frac{1}{3} to fractions with denominator 24.

$$\frac{\frac{11}{24}-\frac{8}{24}}{\frac{1}{8}+\frac{1}{2}}$$

Since \frac{11}{24} and \frac{8}{24} have the same denominator, subtract them by subtracting their numerators.

$$\frac{\frac{11-8}{24}}{\frac{1}{8}+\frac{1}{2}}$$

Subtract 8 from 11 to get 3.

$$\frac{\frac{3}{24}}{\frac{1}{8}+\frac{1}{2}}$$

Reduce the fraction \frac{3}{24} to lowest terms by extracting and canceling out 3.

$$\frac{\frac{1}{8}}{\frac{1}{8}+\frac{1}{2}}$$

Least common multiple of 8 and 2 is 8. Convert \frac{1}{8} and \frac{1}{2} to fractions with denominator 8.

$$\frac{\frac{1}{8}}{\frac{1}{8}+\frac{4}{8}}$$

Since \frac{1}{8} and \frac{4}{8} have the same denominator, add them by adding their numerators.

$$\frac{\frac{1}{8}}{\frac{1+4}{8}}$$

Add 1 and 4 to get 5.

$$\frac{\frac{1}{8}}{\frac{5}{8}}$$

Divide \frac{1}{8} by \frac{5}{8} by multiplying \frac{1}{8} by the reciprocal of \frac{5}{8}.

$$\frac{1}{8}\times \frac{8}{5}$$

Multiply \frac{1}{8} times \frac{8}{5} by multiplying numerator times numerator and denominator times denominator.

$$\frac{1\times 8}{8\times 5}$$

Cancel out 8 in both numerator and denominator.

$$\frac{1}{5}$$

Factor

$$\frac{1}{5} = 0.2$$