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\frac{\left(\frac{1}{2}-\frac{\frac{3}{5}}{3}\right)\left(2-\frac{1}{3}\right)^{3}}{\left(\frac{1}{6}-\frac{2}{3}\right)\left(-1+\frac{1}{3}\right)}
Divide \frac{\frac{1}{2}-\frac{\frac{3}{5}}{3}}{\frac{1}{6}-\frac{2}{3}} by \frac{-1+\frac{1}{3}}{\left(2-\frac{1}{3}\right)^{3}} by multiplying \frac{\frac{1}{2}-\frac{\frac{3}{5}}{3}}{\frac{1}{6}-\frac{2}{3}} by the reciprocal of \frac{-1+\frac{1}{3}}{\left(2-\frac{1}{3}\right)^{3}}.
\frac{\left(\frac{1}{2}-\frac{3}{5\times 3}\right)\left(2-\frac{1}{3}\right)^{3}}{\left(\frac{1}{6}-\frac{2}{3}\right)\left(-1+\frac{1}{3}\right)}
Express \frac{\frac{3}{5}}{3} as a single fraction.
\frac{\left(\frac{1}{2}-\frac{1}{5}\right)\left(2-\frac{1}{3}\right)^{3}}{\left(\frac{1}{6}-\frac{2}{3}\right)\left(-1+\frac{1}{3}\right)}
Cancel out 3 in both numerator and denominator.
\frac{\frac{3}{10}\left(2-\frac{1}{3}\right)^{3}}{\left(\frac{1}{6}-\frac{2}{3}\right)\left(-1+\frac{1}{3}\right)}
Subtract \frac{1}{5} from \frac{1}{2} to get \frac{3}{10}.
\frac{\frac{3}{10}\times \left(\frac{5}{3}\right)^{3}}{\left(\frac{1}{6}-\frac{2}{3}\right)\left(-1+\frac{1}{3}\right)}
Subtract \frac{1}{3} from 2 to get \frac{5}{3}.
\frac{\frac{3}{10}\times \frac{125}{27}}{\left(\frac{1}{6}-\frac{2}{3}\right)\left(-1+\frac{1}{3}\right)}
Calculate \frac{5}{3} to the power of 3 and get \frac{125}{27}.
\frac{\frac{25}{18}}{\left(\frac{1}{6}-\frac{2}{3}\right)\left(-1+\frac{1}{3}\right)}
Multiply \frac{3}{10} and \frac{125}{27} to get \frac{25}{18}.
\frac{\frac{25}{18}}{-\frac{1}{2}\left(-1+\frac{1}{3}\right)}
Subtract \frac{2}{3} from \frac{1}{6} to get -\frac{1}{2}.
\frac{\frac{25}{18}}{-\frac{1}{2}\left(-\frac{2}{3}\right)}
Add -1 and \frac{1}{3} to get -\frac{2}{3}.
\frac{\frac{25}{18}}{\frac{1}{3}}
Multiply -\frac{1}{2} and -\frac{2}{3} to get \frac{1}{3}.
\frac{25}{18}\times 3
Divide \frac{25}{18} by \frac{1}{3} by multiplying \frac{25}{18} by the reciprocal of \frac{1}{3}.
\frac{25}{6}
Multiply \frac{25}{18} and 3 to get \frac{25}{6}.