Solve cosA/1+sinA+1+sinA/cosA=2operatorname{sic}A

$$\frac { \cos A } { 1 + \sin A } + \frac { 1 + \sin A } { \cos A } = 2 \operatorname { sic } A$$

Solve for c

$$c=\frac{-i}{As\cos(A)}$$

$$s\neq 0\text{ and }\nexists n_{1}\in \mathrm{Z}\text{ : }A=\pi n_{1}+\frac{\pi }{2}\text{ and }A\neq 0$$

Steps for Solving Linear Equation

Multiply 2 and i to get 2i.

$$\frac{\cos(A)}{1+\sin(A)}+\frac{1+\sin(A)}{\cos(A)}=2iscA$$

Swap sides so that all variable terms are on the left hand side.

$$2iscA=\frac{\cos(A)}{1+\sin(A)}+\frac{1+\sin(A)}{\cos(A)}$$

The equation is in standard form.

$$2iAsc=\frac{\cos(A)}{\sin(A)+1}+\frac{\sin(A)+1}{\cos(A)}$$

Divide both sides by 2isA.

$$\frac{2iAsc}{2iAs}=\frac{2}{\cos(A)\times \left(2i\right)As}$$

Dividing by 2isA undoes the multiplication by 2isA.

$$c=\frac{2}{\cos(A)\times \left(2i\right)As}$$

Divide \frac{2}{\cos(A)} by 2isA.

$$c=\frac{-i}{As\cos(A)}$$