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Solve for x (complex solution)
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\Delta f=\left(x+\Delta x\right)^{2}-x\left(x+\Delta x\right)+6
Multiply both sides of the equation by x\Delta .
\Delta f=x^{2}+2x\Delta x+\Delta ^{2}x^{2}-x\left(x+\Delta x\right)+6
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(x+\Delta x\right)^{2}.
\Delta f=x^{2}+2x^{2}\Delta +\Delta ^{2}x^{2}-x\left(x+\Delta x\right)+6
Multiply x and x to get x^{2}.
\Delta f=x^{2}+2x^{2}\Delta +\Delta ^{2}x^{2}-\left(x^{2}+\Delta x^{2}\right)+6
Use the distributive property to multiply x by x+\Delta x.
\Delta f=x^{2}+2x^{2}\Delta +\Delta ^{2}x^{2}-x^{2}-\Delta x^{2}+6
To find the opposite of x^{2}+\Delta x^{2}, find the opposite of each term.
\Delta f=2x^{2}\Delta +\Delta ^{2}x^{2}-\Delta x^{2}+6
Combine x^{2} and -x^{2} to get 0.
\Delta f=x^{2}\Delta +\Delta ^{2}x^{2}+6
Combine 2x^{2}\Delta and -\Delta x^{2} to get x^{2}\Delta .
\Delta f=x^{2}\Delta ^{2}+\Delta x^{2}+6
The equation is in standard form.
\frac{\Delta f}{\Delta }=\frac{x^{2}\Delta ^{2}+\Delta x^{2}+6}{\Delta }
Divide both sides by \Delta .
f=\frac{x^{2}\Delta ^{2}+\Delta x^{2}+6}{\Delta }
Dividing by \Delta undoes the multiplication by \Delta .
f=\Delta x^{2}+x^{2}+\frac{6}{\Delta }
Divide x^{2}\Delta +\Delta ^{2}x^{2}+6 by \Delta .