Solve [(3+1)^2]^3/(7-3)^2

$$\frac { [ ( 3 + 1 ) ^ { 2 } ] ^ { 3 } } { ( 7 - 3 ) ^ { 2 } }$$

Evaluate

$$256$$

Solution Steps

To raise a power to another power, multiply the exponents. Multiply 2 and 3 to get 6.

$$\frac{\left(3+1\right)^{6}}{\left(7-3\right)^{2}}$$

Add 3 and 1 to get 4.

$$\frac{4^{6}}{\left(7-3\right)^{2}}$$

Calculate 4 to the power of 6 and get 4096.

$$\frac{4096}{\left(7-3\right)^{2}}$$

Subtract 3 from 7 to get 4.

$$\frac{4096}{4^{2}}$$

Calculate 4 to the power of 2 and get 16.

$$\frac{4096}{16}$$

Divide 4096 by 16 to get 256.

$$256$$

Factor

$$2^{8}$$