Solve frac{[(-3)^{8}]^3*[(-3)^3]}{(-3)^3-(-3)^0}

$$\frac { [ ( - 3 ) ^ { 8 } ] ^ { 3 } \times [ ( - 3 ) ^ { 3 } ] } { ( - 3 ) ^ { 3 } - ( - 3 ) ^ { 0 } }$$

Evaluate

$$\frac{7625597484987}{28}\approx 272342767320.964285714$$

Solution Steps

To raise a power to another power, multiply the exponents. Multiply 8 and 3 to get 24.

$$\frac{\left(-3\right)^{24}\left(-3\right)^{3}}{\left(-3\right)^{3}-\left(-3\right)^{0}}$$

To multiply powers of the same base, add their exponents. Add 24 and 3 to get 27.

$$\frac{\left(-3\right)^{27}}{\left(-3\right)^{3}-\left(-3\right)^{0}}$$

Calculate -3 to the power of 27 and get -7625597484987.

$$\frac{-7625597484987}{\left(-3\right)^{3}-\left(-3\right)^{0}}$$

Calculate -3 to the power of 3 and get -27.

$$\frac{-7625597484987}{-27-\left(-3\right)^{0}}$$

Calculate -3 to the power of 0 and get 1.

$$\frac{-7625597484987}{-27-1}$$

Subtract 1 from -27 to get -28.

$$\frac{-7625597484987}{-28}$$

Fraction \frac{-7625597484987}{-28} can be simplified to \frac{7625597484987}{28} by removing the negative sign from both the numerator and the denominator.

$$\frac{7625597484987}{28}$$

Factor

$$\frac{3 ^ {27}}{2 ^ {2} \cdot 7} = 272342767320\frac{27}{28} = 272342767320.9643$$