Solve for η_g
\eta _{g}=-13
\eta _{g}=13
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\eta _{g}^{2}=25+12^{2}
Calculate 5 to the power of 2 and get 25.
\eta _{g}^{2}=25+144
Calculate 12 to the power of 2 and get 144.
\eta _{g}^{2}=169
Add 25 and 144 to get 169.
\eta _{g}^{2}-169=0
Subtract 169 from both sides.
\left(\eta _{g}-13\right)\left(\eta _{g}+13\right)=0
Consider \eta _{g}^{2}-169. Rewrite \eta _{g}^{2}-169 as \eta _{g}^{2}-13^{2}. The difference of squares can be factored using the rule: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).
\eta _{g}=13 \eta _{g}=-13
To find equation solutions, solve \eta _{g}-13=0 and \eta _{g}+13=0.
\eta _{g}^{2}=25+12^{2}
Calculate 5 to the power of 2 and get 25.
\eta _{g}^{2}=25+144
Calculate 12 to the power of 2 and get 144.
\eta _{g}^{2}=169
Add 25 and 144 to get 169.
\eta _{g}=13 \eta _{g}=-13
Take the square root of both sides of the equation.
\eta _{g}^{2}=25+12^{2}
Calculate 5 to the power of 2 and get 25.
\eta _{g}^{2}=25+144
Calculate 12 to the power of 2 and get 144.
\eta _{g}^{2}=169
Add 25 and 144 to get 169.
\eta _{g}^{2}-169=0
Subtract 169 from both sides.
\eta _{g}=\frac{0±\sqrt{0^{2}-4\left(-169\right)}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and -169 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
\eta _{g}=\frac{0±\sqrt{-4\left(-169\right)}}{2}
Square 0.
\eta _{g}=\frac{0±\sqrt{676}}{2}
Multiply -4 times -169.
\eta _{g}=\frac{0±26}{2}
Take the square root of 676.
\eta _{g}=13
Now solve the equation \eta _{g}=\frac{0±26}{2} when ± is plus. Divide 26 by 2.
\eta _{g}=-13
Now solve the equation \eta _{g}=\frac{0±26}{2} when ± is minus. Divide -26 by 2.
\eta _{g}=13 \eta _{g}=-13
The equation is now solved.
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