Evaluate (complex solution)
\frac{ℓ_{2}}{x}-3=\frac{y}{2}-\frac{2}{3}\text{ and }\frac{y}{2}-\frac{2}{3}=\frac{1}{2}-2z
Solve for x
\left\{\begin{matrix}x=\frac{2ℓ_{2}}{7-4z}\text{, }&ℓ_{2}\neq 0\text{ and }y=\frac{7}{3}-4z\text{ and }z\neq \frac{7}{4}\\x\neq 0\text{, }&y=-\frac{14}{3}\text{ and }ℓ_{2}=0\text{ and }z=\frac{7}{4}\end{matrix}\right.
Solve for ℓ_2
ℓ_{2}=\frac{x\left(7-4z\right)}{2}
x\neq 0\text{ and }y=\frac{7}{3}-4z
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