Solve for x
x=\frac{\delta -8}{2}
Solve for δ
\delta =2\left(x+4\right)
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-2x-8=-\delta
Subtract \delta from both sides. Anything subtracted from zero gives its negation.
-2x=-\delta +8
Add 8 to both sides.
-2x=8-\delta
The equation is in standard form.
\frac{-2x}{-2}=\frac{8-\delta }{-2}
Divide both sides by -2.
x=\frac{8-\delta }{-2}
Dividing by -2 undoes the multiplication by -2.
x=\frac{\delta }{2}-4
Divide -\delta +8 by -2.
\delta -8=2x
Add 2x to both sides. Anything plus zero gives itself.
\delta =2x+8
Add 8 to both sides.
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