Solve delta(602^2)+4(602)+1

$$\delta ( 602 ^ { 2 } ) + 4 ( 602 ) + 1$$

Evaluate

$$362404\delta +2409$$

Solution Steps

Calculate 602 to the power of 2 and get 362404.

$$\delta \times 362404+4\times 602+1$$

Multiply 4 and 602 to get 2408.

$$\delta \times 362404+2408+1$$

Add 2408 and 1 to get 2409.

$$\delta \times 362404+2409$$

Differentiate w.r.t. δ

$$362404$$

Steps Using Derivative Rule for Sum

Calculate 602 to the power of 2 and get 362404.

$$\frac{\mathrm{d}}{\mathrm{d}\delta }(\delta \times 362404+4\times 602+1)$$

Multiply 4 and 602 to get 2408.

$$\frac{\mathrm{d}}{\mathrm{d}\delta }(\delta \times 362404+2408+1)$$

Add 2408 and 1 to get 2409.

$$\frac{\mathrm{d}}{\mathrm{d}\delta }(\delta \times 362404+2409)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$362404\delta ^{1-1}$$

Subtract 1 from 1.

$$362404\delta ^{0}$$

For any term t except 0, t^{0}=1.

$$362404\times 1$$

For any term t, t\times 1=t and 1t=t.

$$362404$$