Solve for u
u=\frac{\cos(x)-b}{12}
Solve for b
b=\cos(x)-12u
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b+12u=\cos(x)
Swap sides so that all variable terms are on the left hand side.
12u=\cos(x)-b
Subtract b from both sides.
\frac{12u}{12}=\frac{\cos(x)-b}{12}
Divide both sides by 12.
u=\frac{\cos(x)-b}{12}
Dividing by 12 undoes the multiplication by 12.
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