Solve cos(x)-1/5x^3G2=-3

$$\cos ( x ) - \frac{ 1 }{ 5 } { x }^{ 3 } G2=-3$$

Solve for G_2

$$G_{2}=\frac{5\left(\cos(x)+3\right)}{x^{3}}$$

$$x\neq 0$$

Steps for Solving Linear Equation

Multiply -1 and \frac{1}{5} to get -\frac{1}{5}.

$$\cos(x)-\frac{1}{5}x^{3}G_{2}=-3$$

Subtract \cos(x) from both sides.

$$-\frac{1}{5}x^{3}G_{2}=-3-\cos(x)$$

The equation is in standard form.

$$\left(-\frac{x^{3}}{5}\right)G_{2}=-\cos(x)-3$$

Divide both sides by -\frac{1}{5}x^{3}.

$$\frac{\left(-\frac{x^{3}}{5}\right)G_{2}}{-\frac{x^{3}}{5}}=\frac{-\cos(x)-3}{-\frac{x^{3}}{5}}$$

Dividing by -\frac{1}{5}x^{3} undoes the multiplication by -\frac{1}{5}x^{3}.

$$G_{2}=\frac{-\cos(x)-3}{-\frac{x^{3}}{5}}$$

Divide -3-\cos(x) by -\frac{1}{5}x^{3}.

$$G_{2}=\frac{5\left(\cos(x)+3\right)}{x^{3}}$$