Solve alpha=-(9*2/5-9/3:3)2,5-5

$$\alpha = - ( 9 \cdot \frac { 2 } { 5 } - \frac { 9 } { 3 } : 3 ) 2,5 - 5$$

Solve for α

$$\alpha =-11,5$$

Steps for Solving Linear Equation

Express 9\times \frac{2}{5} as a single fraction.

$$\alpha =\left(-\left(\frac{9\times 2}{5}-\frac{\frac{9}{3}}{3}\right)\right)\times 2,5-5$$

Multiply 9 and 2 to get 18.

$$\alpha =\left(-\left(\frac{18}{5}-\frac{\frac{9}{3}}{3}\right)\right)\times 2,5-5$$

Divide 9 by 3 to get 3.

$$\alpha =\left(-\left(\frac{18}{5}-\frac{3}{3}\right)\right)\times 2,5-5$$

Divide 3 by 3 to get 1.

$$\alpha =\left(-\left(\frac{18}{5}-1\right)\right)\times 2,5-5$$

Convert 1 to fraction \frac{5}{5}.

$$\alpha =\left(-\left(\frac{18}{5}-\frac{5}{5}\right)\right)\times 2,5-5$$

Since \frac{18}{5} and \frac{5}{5} have the same denominator, subtract them by subtracting their numerators.

$$\alpha =\left(-\frac{18-5}{5}\right)\times 2,5-5$$

Subtract 5 from 18 to get 13.

$$\alpha =-\frac{13}{5}\times 2,5-5$$

Convert decimal number 2,5 to fraction \frac{25}{10}. Reduce the fraction \frac{25}{10} to lowest terms by extracting and canceling out 5.

$$\alpha =-\frac{13}{5}\times \frac{5}{2}-5$$

Multiply -\frac{13}{5} times \frac{5}{2} by multiplying numerator times numerator and denominator times denominator.

$$\alpha =\frac{-13\times 5}{5\times 2}-5$$

Cancel out 5 in both numerator and denominator.

$$\alpha =\frac{-13}{2}-5$$

Fraction \frac{-13}{2} can be rewritten as -\frac{13}{2} by extracting the negative sign.

$$\alpha =-\frac{13}{2}-5$$

Convert 5 to fraction \frac{10}{2}.

$$\alpha =-\frac{13}{2}-\frac{10}{2}$$

Since -\frac{13}{2} and \frac{10}{2} have the same denominator, subtract them by subtracting their numerators.

$$\alpha =\frac{-13-10}{2}$$

Subtract 10 from -13 to get -23.

$$\alpha =-\frac{23}{2}$$

Assign α

$$\alpha ≔-11,5$$