Solve alpha=3/11gamma+psi_{gamma}

$$\alpha = \frac { 3 } { 11 } \gamma + \psi _ { \gamma }$$

Solve for γ

$$\gamma =\frac{11\left(\alpha -\psi _{γ}\right)}{3}$$

Steps for Solving Linear Equation

Swap sides so that all variable terms are on the left hand side.

$$\frac{3}{11}\gamma +\psi _{γ}=\alpha$$

Subtract \psi _{γ} from both sides.

$$\frac{3}{11}\gamma =\alpha -\psi _{γ}$$

Divide both sides of the equation by \frac{3}{11}, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{\frac{3}{11}\gamma }{\frac{3}{11}}=\frac{\alpha -\psi _{γ}}{\frac{3}{11}}$$

Dividing by \frac{3}{11} undoes the multiplication by \frac{3}{11}.

$$\gamma =\frac{\alpha -\psi _{γ}}{\frac{3}{11}}$$

Divide \alpha -\psi _{γ} by \frac{3}{11} by multiplying \alpha -\psi _{γ} by the reciprocal of \frac{3}{11}.

$$\gamma =\frac{11\alpha -11\psi _{γ}}{3}$$

Solve for α

$$\alpha =\frac{3\gamma }{11}+\psi _{γ}$$