Solve alpha+beta+3r=lambda

$$\alpha + \beta + 3 r = \lambda$$

Solve for r

$$r=\frac{\lambda -\beta -\alpha }{3}$$

Steps for Solving Linear Equation

Subtract \alpha from both sides.

$$\beta +3r=\lambda -\alpha$$

Subtract \beta from both sides.

$$3r=\lambda -\alpha -\beta$$

The equation is in standard form.

$$3r=\lambda -\beta -\alpha$$

Divide both sides by 3.

$$\frac{3r}{3}=\frac{\lambda -\beta -\alpha }{3}$$

Dividing by 3 undoes the multiplication by 3.

$$r=\frac{\lambda -\beta -\alpha }{3}$$

Solve for α

$$\alpha =-3r+\lambda -\beta$$

Solution Steps

Subtract \beta from both sides.

$$\alpha +3r=\lambda -\beta$$

Subtract 3r from both sides.

$$\alpha =\lambda -\beta -3r$$