Solve for Δ
\Delta =-\frac{2.248488-6x}{x^{3}}
x\neq 0
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\Delta x^{3}+2.248488=6x
Add 6x to both sides. Anything plus zero gives itself.
\Delta x^{3}=6x-2.248488
Subtract 2.248488 from both sides.
x^{3}\Delta =6x-2.248488
The equation is in standard form.
\frac{x^{3}\Delta }{x^{3}}=\frac{6x-2.248488}{x^{3}}
Divide both sides by x^{3}.
\Delta =\frac{6x-2.248488}{x^{3}}
Dividing by x^{3} undoes the multiplication by x^{3}.
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