Solve Deltax=55b+2cx

$$\Delta x = 55 b + 2 c x$$

Solve for c (complex solution)

$$\left\{\begin{matrix}c=\frac{\Delta }{2}-\frac{55b}{2x}\text{, }&x\neq 0\\c\in \mathrm{C}\text{, }&b=0\text{ and }x=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Swap sides so that all variable terms are on the left hand side.

$$55b+2cx=\Delta x$$

Subtract 55b from both sides.

$$2cx=\Delta x-55b$$

The equation is in standard form.

$$2xc=x\Delta -55b$$

Divide both sides by 2x.

$$\frac{2xc}{2x}=\frac{x\Delta -55b}{2x}$$

Dividing by 2x undoes the multiplication by 2x.

$$c=\frac{x\Delta -55b}{2x}$$

Divide \Delta x-55b by 2x.

$$c=\frac{\Delta }{2}-\frac{55b}{2x}$$

Solve for b

$$b=\frac{x\left(\Delta -2c\right)}{55}$$

Steps for Solving Linear Equation

Swap sides so that all variable terms are on the left hand side.

$$55b+2cx=\Delta x$$

Subtract 2cx from both sides.

$$55b=\Delta x-2cx$$

The equation is in standard form.

$$55b=x\Delta -2cx$$

Divide both sides by 55.

$$\frac{55b}{55}=\frac{x\left(\Delta -2c\right)}{55}$$

Dividing by 55 undoes the multiplication by 55.

$$b=\frac{x\left(\Delta -2c\right)}{55}$$

Solve for c

$$\left\{\begin{matrix}c=\frac{\Delta }{2}-\frac{55b}{2x}\text{, }&x\neq 0\\c\in \mathrm{R}\text{, }&b=0\text{ and }x=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Swap sides so that all variable terms are on the left hand side.

$$55b+2cx=\Delta x$$

Subtract 55b from both sides.

$$2cx=\Delta x-55b$$

The equation is in standard form.

$$2xc=x\Delta -55b$$

Divide both sides by 2x.

$$\frac{2xc}{2x}=\frac{x\Delta -55b}{2x}$$

Dividing by 2x undoes the multiplication by 2x.

$$c=\frac{x\Delta -55b}{2x}$$

Divide \Delta x-55b by 2x.

$$c=\frac{\Delta }{2}-\frac{55b}{2x}$$