\Delta _ { 10 } = \int _ { 0 } ^ { 6 } ( - \frac { 3 x ^ { 2 } } { 2 } + 15 x ) \cdot ( 0.5 x ) d x + \int _ { 6 } ^ { 12 } ( - \frac { 3 x ^ { 2 } } { 2 } + 18 x ) \cdot ( - 0.5 x + 6 ) d x
Solve for Δ_10
\Delta _{10}=702
Assign Δ_10
\Delta _{10}≔702
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