Solve Delta=4^2-4(4(-10/3))

$$\Delta = 4 ^ { 2 } - 4 ( 4 ( - \frac { 10 } { 3 } ) )$$

Solve for Δ

$$\Delta =\frac{208}{3}\approx 69.333333333$$

Steps for Solving Linear Equation

Calculate 4 to the power of 2 and get 16.

$$\Delta =16-4\times 4\left(-\frac{10}{3}\right)$$

Multiply 4 and 4 to get 16.

$$\Delta =16-16\left(-\frac{10}{3}\right)$$

Express 16\left(-\frac{10}{3}\right) as a single fraction.

$$\Delta =16-\frac{16\left(-10\right)}{3}$$

Multiply 16 and -10 to get -160.

$$\Delta =16-\frac{-160}{3}$$

Fraction \frac{-160}{3} can be rewritten as -\frac{160}{3} by extracting the negative sign.

$$\Delta =16-\left(-\frac{160}{3}\right)$$

The opposite of -\frac{160}{3} is \frac{160}{3}.

$$\Delta =16+\frac{160}{3}$$

Convert 16 to fraction \frac{48}{3}.

$$\Delta =\frac{48}{3}+\frac{160}{3}$$

Since \frac{48}{3} and \frac{160}{3} have the same denominator, add them by adding their numerators.

$$\Delta =\frac{48+160}{3}$$

Add 48 and 160 to get 208.

$$\Delta =\frac{208}{3}$$

Assign Δ

$$\Delta ≔\frac{208}{3}$$