\{ y = - \frac { 1 } { 2 } x + 3
Solve for x
x=6-2y
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-\frac{1}{2}x+3=y
Swap sides so that all variable terms are on the left hand side.
-\frac{1}{2}x=y-3
Subtract 3 from both sides.
\frac{-\frac{1}{2}x}{-\frac{1}{2}}=\frac{y-3}{-\frac{1}{2}}
Multiply both sides by -2.
x=\frac{y-3}{-\frac{1}{2}}
Dividing by -\frac{1}{2} undoes the multiplication by -\frac{1}{2}.
x=6-2y
Divide y-3 by -\frac{1}{2} by multiplying y-3 by the reciprocal of -\frac{1}{2}.
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