\{ x + y + x y = 3
Solve for x
x=-\frac{y-3}{y+1}
y\neq -1
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x+xy=3-y
Subtract y from both sides.
\left(1+y\right)x=3-y
Combine all terms containing x.
\left(y+1\right)x=3-y
The equation is in standard form.
\frac{\left(y+1\right)x}{y+1}=\frac{3-y}{y+1}
Divide both sides by 1+y.
x=\frac{3-y}{y+1}
Dividing by 1+y undoes the multiplication by 1+y.
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