Solve {8+[9-(6-(-5-4)*2)]div5}div5

$$\{ 8 + [ 9 - ( 6 - ( - 5 - 4 ) \cdot 2 ) ] \div 5 \} \div 5$$

Evaluate

$$1$$

Solution Steps

Subtract 4 from -5 to get -9.

$$\frac{8+\frac{9-\left(6-\left(-9\times 2\right)\right)}{5}}{5}$$

Multiply -9 and 2 to get -18.

$$\frac{8+\frac{9-\left(6-\left(-18\right)\right)}{5}}{5}$$

The opposite of -18 is 18.

$$\frac{8+\frac{9-\left(6+18\right)}{5}}{5}$$

Add 6 and 18 to get 24.

$$\frac{8+\frac{9-24}{5}}{5}$$

Subtract 24 from 9 to get -15.

$$\frac{8+\frac{-15}{5}}{5}$$

Divide -15 by 5 to get -3.

$$\frac{8-3}{5}$$

Subtract 3 from 8 to get 5.

$$\frac{5}{5}$$

Divide 5 by 5 to get 1.

$$1$$

Factor

$$1$$