Solve {41/2+(51/3*3)}-22/3

$$\{ 4 \frac { 1 } { 2 } + ( 5 \frac { 1 } { 3 } \times 3 ) \} - 2 \frac { 2 } { 3 }$$

Evaluate

$$\frac{107}{6}\approx 17.833333333$$

Solution Steps

Multiply 4 and 2 to get 8.

$$\frac{8+1}{2}+\frac{5\times 3+1}{3}\times 3-\frac{2\times 3+2}{3}$$

Add 8 and 1 to get 9.

$$\frac{9}{2}+\frac{5\times 3+1}{3}\times 3-\frac{2\times 3+2}{3}$$

Multiply 5 and 3 to get 15.

$$\frac{9}{2}+\frac{15+1}{3}\times 3-\frac{2\times 3+2}{3}$$

Add 15 and 1 to get 16.

$$\frac{9}{2}+\frac{16}{3}\times 3-\frac{2\times 3+2}{3}$$

Cancel out 3 and 3.

$$\frac{9}{2}+16-\frac{2\times 3+2}{3}$$

Convert 16 to fraction \frac{32}{2}.

$$\frac{9}{2}+\frac{32}{2}-\frac{2\times 3+2}{3}$$

Since \frac{9}{2} and \frac{32}{2} have the same denominator, add them by adding their numerators.

$$\frac{9+32}{2}-\frac{2\times 3+2}{3}$$

Add 9 and 32 to get 41.

$$\frac{41}{2}-\frac{2\times 3+2}{3}$$

Multiply 2 and 3 to get 6.

$$\frac{41}{2}-\frac{6+2}{3}$$

Add 6 and 2 to get 8.

$$\frac{41}{2}-\frac{8}{3}$$

Least common multiple of 2 and 3 is 6. Convert \frac{41}{2} and \frac{8}{3} to fractions with denominator 6.

$$\frac{123}{6}-\frac{16}{6}$$

Since \frac{123}{6} and \frac{16}{6} have the same denominator, subtract them by subtracting their numerators.

$$\frac{123-16}{6}$$

Subtract 16 from 123 to get 107.

$$\frac{107}{6}$$

Factor

$$\frac{107}{2 \cdot 3} = 17\frac{5}{6} = 17.833333333333332$$