\{ 3 x + y = 6
Solve for x
x=-\frac{y}{3}+2
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3x=6-y
Subtract y from both sides.
\frac{3x}{3}=\frac{6-y}{3}
Divide both sides by 3.
x=\frac{6-y}{3}
Dividing by 3 undoes the multiplication by 3.
x=-\frac{y}{3}+2
Divide 6-y by 3.
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