\{ 3 x + 2 y = - 1
Solve for x
x=\frac{-2y-1}{3}
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3x=-1-2y
Subtract 2y from both sides.
3x=-2y-1
The equation is in standard form.
\frac{3x}{3}=\frac{-2y-1}{3}
Divide both sides by 3.
x=\frac{-2y-1}{3}
Dividing by 3 undoes the multiplication by 3.
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