\{ 2 x + 3 y = 2
Solve for x
x=-\frac{3y}{2}+1
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2x=2-3y
Subtract 3y from both sides.
\frac{2x}{2}=\frac{2-3y}{2}
Divide both sides by 2.
x=\frac{2-3y}{2}
Dividing by 2 undoes the multiplication by 2.
x=-\frac{3y}{2}+1
Divide 2-3y by 2.
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