Solve {12-[(-12:-3)+(3)^2-(2*-1)^3]+10}=

$$\{ 12 - [ ( - 12 : - 3 ) + ( 3 ) ^ { 2 } - ( 2 \cdot - 1 ) ^ { 3 } ] + 10 \} =$$

Evaluate

$$1$$

Solution Steps

Divide -12 by -3 to get 4.

$$12-\left(4+3^{2}-\left(2\left(-1\right)\right)^{3}\right)+10$$

Calculate 3 to the power of 2 and get 9.

$$12-\left(4+9-\left(2\left(-1\right)\right)^{3}\right)+10$$

Add 4 and 9 to get 13.

$$12-\left(13-\left(2\left(-1\right)\right)^{3}\right)+10$$

Multiply 2 and -1 to get -2.

$$12-\left(13-\left(-2\right)^{3}\right)+10$$

Calculate -2 to the power of 3 and get -8.

$$12-\left(13-\left(-8\right)\right)+10$$

The opposite of -8 is 8.

$$12-\left(13+8\right)+10$$

Add 13 and 8 to get 21.

$$12-21+10$$

Subtract 21 from 12 to get -9.

$$-9+10$$

Add -9 and 10 to get 1.

$$1$$

Factor

$$1$$