Solve {-2*[(-2)^4:8]-4*(15-sqrt{25})}*(-6)+(+6)=

$$\{ - 2 \times [ ( - 2 ) ^ { 4 } : 8 ] - 4 \times ( 15 - \sqrt { 25 } ) \} \times ( - 6 ) + ( + 6 ) =$$

Evaluate

$$270$$

Solution Steps

Calculate -2 to the power of 4 and get 16.

$$\left(-2\times \frac{16}{8}-4\left(15-\sqrt{25}\right)\right)\left(-6\right)+6$$

Divide 16 by 8 to get 2.

$$\left(-2\times 2-4\left(15-\sqrt{25}\right)\right)\left(-6\right)+6$$

Multiply -2 and 2 to get -4.

$$\left(-4-4\left(15-\sqrt{25}\right)\right)\left(-6\right)+6$$

Calculate the square root of 25 and get 5.

$$\left(-4-4\left(15-5\right)\right)\left(-6\right)+6$$

Subtract 5 from 15 to get 10.

$$\left(-4-4\times 10\right)\left(-6\right)+6$$

Multiply 4 and 10 to get 40.

$$\left(-4-40\right)\left(-6\right)+6$$

Subtract 40 from -4 to get -44.

$$-44\left(-6\right)+6$$

Multiply -44 and -6 to get 264.

$$264+6$$

Add 264 and 6 to get 270.

$$270$$

Factor

$$2\times 3^{3}\times 5$$